amplitude modulation exam solutions
with a message frequency of 3 kHz. Solution: The bandwidth \(BW\) of an AM signal is twice the maximum frequency of the message signal: \[ BW = 2 f_m \] Given \(f_m = 3\, \text{kHz}\), \[ BW = 2 \times 3\, \text{kHz} = 6\, \te